2.45x^2+x=1

Solution for 2.45x^2+x=1 equation:

2.45x^2+x=1

We move all terms to the left:

2.45x^2+x-(1)=0

a = 2.45; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·2.45·(-1)
Δ = 10.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{10.8}}{2*2.45}=\frac{-1-\sqrt{10.8}}{4.9}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{10.8}}{2*2.45}=\frac{-1+\sqrt{10.8}}{4.9}
$